Question

check whether 1728 is a perfect cube by using prime factorisation​

Answer 1

Answer:

The number 1728 on prime factorization gives 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3. On combining the prime factors in groups of 3 gives 12. So, the cube root of 1728 = ∛(2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3) = 12 (perfect cube).