Question

Check whether 18^n can end with the digit 0 or 5 for any natural number 'n'​

Answer 1

Answer:

no

Step-by-step explanation:

Let us think of some numbers which end

the digit 0

10 = 5x 2

100 = 2 x 2x5x5

Many more...

Now, Clearly we can see that numbers

ending with O has prime factors as 2 and

5, take any number ending with digit 0, it

will do have 2 and 5 as a factor.

But,

8^n =(4x 2) ^n

It doesn't have 5 as it's factor thus 8^ n

cannot end with zero for any natural

number n.