Math, asked by nandu9655, 9 months ago

Check whether -2, 2, -2, 2, -2, ….. is an AP or not.

Answers

Answered by piyushkhaparde675
3

Answer:

No it is not in the form of Ap

Step-by-step explanation:

here a= -2

d= 2-(-2) = 4

now let's take the 3rd Term i.e -2 ; d= -2-2 = -4

as difference (d) is not in equal So, it is not in Ap

Answered by aishwaryahk
0

Answer:

The given series -2, 2, -2, 2, -2,..... is not in A. P.

Step-by-step explanation:

The arithmetic progression is given by

-2, 2, -2. 2, -2,......

The first term of the arithmetic progression is given by

a = -2

The comon difference of the A. P is given by

Common difference = second term - first term

d  = 2 - (-2)

d = 4

Therefore the 3rd term of the arithmetic progression is given by

T_{3} = a +(n-1)d

    = -2 + (3-1)(4)

T_{3}= 6

The 3rd term of A. P is not in the given series

Therefore the given series -2, 2, -2, 2, -2,..... is not in A. P.

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