Question

check whether 2/3 and 3 are the zeros of the polynomial when p(x)=
$3 {x}^{2} - 11x + 6$


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Answer 1

Answer:

p(2/3)=3*(2/3)^2-11(2/3)+6=4/3-22/3+6=4-22+18/3=0/3=0

p(2/3)=0 so 2/3 is zero of polynomial p(x)

p(3)=3(3^2)-11(3)+6=27-33+6=33-33=0

p(4)=0 so 3 is zero of polynomial of p(x)

Hope this helps you

Mark as Brainliest answer please

Answer 2

GIVEN:

→$3x^{2}-11x+6$

TO CHECK:

→Whether $\dfrac{2}{3}$ and 3 are the zeroes of polynomial p(x).

CHECK:

We can check the above by finding the zeroes of p(x).We will be trying to find it's zeroes by factorisation.

______________________________________

Let p(x) =0.

=>$3 {x}^{2} - 11x + 6 = 0$

=>$3x^{2} -2x - 9x + 6 = 0$

=>$x(3x-2) -3(3x-2)=0$

=>$(x-3)(3x-2)=0$

=>$(x-3) =0$ | =>$(3x-2) =0$

=>$x = 3$ | =>$x =\dfrac{2}{3}$

=>$x=3, \dfrac{2}{3}$

Hence the zeroes of p(x) are $2 \:and\:\dfrac{2}{3}$.

Hence checked.

$\huge\orange{\boxed{x =3,\dfrac{2}{3}}}$