check whether 2, 3 is a solution of the equation 7 x - 3 y = 2 and (a, a+1) is a solution of the equation then find a and b .
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Answered by
16
Answer:
Checking whether ( 2,3 ) is the solution:
⇒ Eqn: 7x - 3y = 2
Substituting x = 2 and y = 3 we get,
⇒ 7 ( 2 ) - 3 ( 3 ) = 2
⇒ 14 - 9 = 2
⇒ 5 = 2 which is not true.
Therefore 2,3 is not a solution of the equation 7x - 3y = 2
Finding 'a' if ( a, a+1 ) is the solution of the equation.
⇒ 7 ( a ) - 3 ( a + 1 ) = 2
⇒ 7a - 3a - 3 = 2
⇒ 4a - 3 = 2
⇒ 4a = 2 + 3
⇒ 4a = 5
⇒ a = 5/4
Therefore value of 'a' is 5/4
Hope it helped !!
Answered by
33
To check 2,3 is a solution put
➭ x = 2
➭ y = 3
_______________[Put Values]
7x - 3y = 2
7(2) - 3(3) = 2
⇒ 14 - 9 = 2
⇒ 5 ≠ 2
Hence, 2 and 3 are not solutions.
___________________________
Now put (a, a + 1)
7(a) - 3(a + 1) = 2
⇒ 7a - 3a - 3 = 2
⇒ 7a - 3a - 3 = 2
⇒ 7a - 3a = 2 + 3
⇒ 4a = 5
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