Question

check whether -2 and -3 are the zeros of p(x)=x^2+5x+6

Answer 1

Answer:

put x= - 2

p(-2) = (-2)² + 5 (-2) +6

= 4 - 10 + 6

=0

now put x = - 3

p(-3) = (-3)² +5(-3) +6

= 9 - 15 +6

=0

so - 2 and - 3 are zeroes of polynomial.

Answer 2

Answer:

-2 and -3 are zeros of polynomial p(X)=x^2+5x+6

Step-by-step explanation:

p(X)=x^2+5x+6

putting X=-2

p(X)=(-2)^2+5(-2)+6

p(X)=4-10+6

p(X)=0

putting X=-3 we get

p(X)=(-3)^2+5(-3)+6

p(X)=9-15+6

p(X)=15-15

p(X)=0