Math, asked by samuelncd614, 8 months ago

check whether 200 is any term of the following sequence 3,7,11,15​

Answers

Answered by rahul100404
0

Step-by-step explanation:

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Answered by Tanujrao36
20

\huge\bf{\underline{\underline{\red{Question}}}}

\bf{ \underline{ \orange{Given\:-}}}

\sf{a\:=\:3}

\sf{d\:=\:4}

\bf{ \underline{ \orange{To\:Find\:-}}}

\sf{Check\: whether\:200\:is\:any\:term\:of\:this\:}\sf{Sequence}

\huge\bf{\underline{\underline{\red{Solution}}}}

\sf{ \boxed{\ a_{n}\:=\:a+(n-1)d}}

If the value of n will be any positive integar than it will possible that 200 is term of this sequence.

\bf{Put\:value\:in\:formula}

\implies\sf{200\:=\:3+(n-1)4}

\implies\sf{200-3\:=\:(n-1)4}

\implies\sf{n-1\:=\:\dfrac{197}{4}}

\implies\sf{n\:=\:\dfrac{197}{4}+1}

\implies\sf{n\:=\:\dfrac{197+4}{4}}

\implies\sf{n\:=\:\dfrac{201}{4}}

\implies\sf{n\:=\:50.25}

\sf{It\:is\:not\: possible\:that\:n\:is\:in\: decimal\:So,\:200\:}\sf{is\:not\:a\: term\:of\:this\: sequence}

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