Question

check whether 234 is a term of AP 3 ,7, 11 ,15​

Answer 1

Answer:

5 is the answer

Step-by-step explanation:

please give me brainlyest

Answer 2

$\sf\huge\bold{Solution}$

we have given 234 and series of AP 3,7,11,15

Here,$\sf a_{n}$ will be 234

first term (a)=3

second term( $a_{2}$)=7

Common difference (d) = $\sf\bold{a_{2}-a_{1}}$

$\longmapsto \: d = 7 - 3 = 4$

Here ,we obtain d =4

a=3 and an=234

To check whether 234 is a term of given AP or not if the value of nth term comes in value saying any constant value then it will be a term and if it comes in fraction or decimal form then it will not be a term of the given AP.

$\sf\boxed{a_{n} = a + (n - 1)d}$

$\sf\longmapsto234 = 3 + (n - 1)4$

$\sf\longmapsto234 - 3 = 4n - 4$

$\sf\longmapsto231 + 4 = 4n$

$\sf\longmapsto235 = 4n$

$\sf\bold{n = \dfrac{235}{4} = 58.75}$

Here, we see that value of 'n' comes in decimal form.

=>Hence,it is not a term of the given AP.