Question

Check whether (28 )^n can end with the digit 0 for any natural number n.

Answer 1

Answer:

It can be observed that 5 is not in the prime factorisation of (22x7)n or 28n. Hence, for any value of n, 28n will not be divisible by 5. Therefore, 28n cannot end with the digit 0 for any natural number n.

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