Check whether 3 and -2 are the zeroes of the polynomial p(x) when p(x) =x²-x-6.
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Taking 3 as x,
= ( 3 )² - 3 - 6 = 9 - 9 = O
Taking -2 as x,
= ( -2 ) ² - ( -2) - 6 = 4 + 2 - 6 = 0
Thus, both 3 & -2 are the zeros of the polynomial
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given zeroes = 3, -2
polynomial p(x) = x² - x - 6
For polynomials,
x² - (sum of zeroes)x + (product of zeroes)
= x² - [ 3 + (-2) ]x + [ 3 × (-2) ]
= x² - [ 1 ]x + [ -6 ]
= x² - x - 6
Therefore, we can say that 3 and -2 are the zeroes of the polynomial x² - x - 6
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