check whether 3 and -2 are the zeros of the polynomial x square -x -6
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Answered by
33
Hi,
P ( X ) = X² - X - 6
Putting X = 3
(3)² - 3 - 6
=> 9 - 9
=> 0
Remainder = 0 . So 3 is a zero of the given quadratic polynomial.
(2) P ( X ) = X² - X - 6
P(-2) = (-2)² - (-2) - 6
=> 4 + 2 - 6
=> 6 - 6
=> 0
Remainder = 0 , so -2 is a zero of the given quadratic polynomial.
In both the cases remainder is equal to 0 . so 3 and -2 are two zeroes of the given quadratic polynomial X²-X - 6.
Hope it will help you :-)
P ( X ) = X² - X - 6
Putting X = 3
(3)² - 3 - 6
=> 9 - 9
=> 0
Remainder = 0 . So 3 is a zero of the given quadratic polynomial.
(2) P ( X ) = X² - X - 6
P(-2) = (-2)² - (-2) - 6
=> 4 + 2 - 6
=> 6 - 6
=> 0
Remainder = 0 , so -2 is a zero of the given quadratic polynomial.
In both the cases remainder is equal to 0 . so 3 and -2 are two zeroes of the given quadratic polynomial X²-X - 6.
Hope it will help you :-)
Answered by
16
x2 - x - 6
= x2 - 3x + 2x - 6
= x(x - 3) + 2(x - 3)
= (x - 3) (x + 2)
x - 3 = 0
=> x = 3
=> x = -2
Therefore, 3 and -2 are the zeroes of the polynomial x2 - x - 6.
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