check whether 301 is a term of AP 5, 11 ,17 ,23 .......? please show the answer step by step
Answers
Answered by
2
Given that :
a = 5
d = a2 - a1 = 11 - 5 = 6
an = a + ( n - 1 ) d
301 = 5 + ( n - 1 ) 6
301 - 5 = 6n - 6
296 + 6 = 6n
302 = 6n
n = 302 / 6
n = 50.33
But the value of n can't be in decimal
Hence 301 is not a term of this A.P
HOPE IT HELPS YOU :-)
a = 5
d = a2 - a1 = 11 - 5 = 6
an = a + ( n - 1 ) d
301 = 5 + ( n - 1 ) 6
301 - 5 = 6n - 6
296 + 6 = 6n
302 = 6n
n = 302 / 6
n = 50.33
But the value of n can't be in decimal
Hence 301 is not a term of this A.P
HOPE IT HELPS YOU :-)
udit43:
Most welcome
Answered by
3
Hiii friend,
AP = 5 , 11 , 17 , 23
Here,
First term (A) = 5
Common difference (D) = 6
Tn = 301
a + (N-1) × D = 301
5 + (N-1) × 6 = 301
5 + 6N -6 = 301
6N = 301+1
6N = 302
N = 302/6 is not divisible by 6
So 301 isn't a term of the given AP.
HOPE IT WILL HELP YOU.... :-)
AP = 5 , 11 , 17 , 23
Here,
First term (A) = 5
Common difference (D) = 6
Tn = 301
a + (N-1) × D = 301
5 + (N-1) × 6 = 301
5 + 6N -6 = 301
6N = 301+1
6N = 302
N = 302/6 is not divisible by 6
So 301 isn't a term of the given AP.
HOPE IT WILL HELP YOU.... :-)
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