Question

Check whether 307 is a term of the list of numbers 6, 13, 20, 27, …..​

Answer 1

Answer:

The given sequence is 3, 8, 13, 18, ....78.

'a' = 3, 'd' = 5, last term = 78, 'n' = ?

t  

n

​  

=a+(n−1)d

⟹78=3+(n−1)5

⟹78=3+5n−5

⟹78=5n−2

⟹5n=80orn=16.

The 16th term is 78.

Step-by-step explanation:

Answer 2

Answer:

let the a nth term be 307

term of list of number 6,13,20,27....

a=6,difference=7

an=a+(n‐1)d

307=6+7n‐7

307=7n‐1

7n=307‐(‐1)

7n=308

n=308÷7

44

so yes 307 is the term of the list of numbers