check whether (39)^n is divisible by 3 for any n ,not a natural number.
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For n = 1, p (1) = 39 which is divisible by 3. So, the result is true for n = 1. ... ∴ p (k + 1) = (39)k+1 is divisible by 3. Thus result is true for n = k + 1 if it is true for n = k.
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