check whether 3x-7 is a factor of polynomial 6x cube + x square - 26x -25
Mohanchandrabhatt:
Please mark any one answer as a brillianist answer
Answers
Answered by
15
Let p(x) = 6x³ + x² - 26x -25
g(x) = 3x - 7
g(x) = 0
3x - 7 = 0
3x = 0 + 7
x = 7 / 3
Putting x = 7 / 3 in p(x)
p(7/3) = 6 ( 7 / 3 )³ + ( 7 / 3 )² - 26 ( 7 / 3 ) - 25
p(7/3) = 6 * 343 / 27 + 49 / 9 - 182 / 3 - 25
p(7/3) = 686 / 9 + 49 / 9 - 546 / 9 - 225 / 9
p(7/3) = 686 + 49 - 546 - 225 / 9
p(7/3) = 735 - 771 / 9
p(7/3) = -36/9
p(7/3) = -4
As p(7/3) ≠ 0 so g(x) is not a factor of p(x).
So 3x-7 is not a factor of 6x³ - x² - 26x -25
g(x) = 3x - 7
g(x) = 0
3x - 7 = 0
3x = 0 + 7
x = 7 / 3
Putting x = 7 / 3 in p(x)
p(7/3) = 6 ( 7 / 3 )³ + ( 7 / 3 )² - 26 ( 7 / 3 ) - 25
p(7/3) = 6 * 343 / 27 + 49 / 9 - 182 / 3 - 25
p(7/3) = 686 / 9 + 49 / 9 - 546 / 9 - 225 / 9
p(7/3) = 686 + 49 - 546 - 225 / 9
p(7/3) = 735 - 771 / 9
p(7/3) = -36/9
p(7/3) = -4
As p(7/3) ≠ 0 so g(x) is not a factor of p(x).
So 3x-7 is not a factor of 6x³ - x² - 26x -25
Answered by
8
Let p(x) = 6x³ + x² - 26x -25
g(x) = 3x - 7
g(x) = 0
3x - 7 = 0
3x = 0 + 7
x = 7 / 3
Putting x = 7 / 3 in p(x)
p(7/3) = 6 ( 7 / 3 )³ + ( 7 / 3 )² - 26 ( 7 / 3 ) - 25
p(7/3) = 6 * 343 / 27 + 49 / 9 - 182 / 3 - 25
p(7/3) = 686 / 9 + 49 / 9 - 546 / 9 - 225 / 9
p(7/3) = 686 + 49 - 546 - 225 / 9
p(7/3) = 735 - 771 / 9
p(7/3) = -36/9
p(7/3) = -4
As p(7/3) ≠ 0 so g(x) is not a factor of p(x).
So 3x-7 is not a factor of 6x³ - x² - 26x -25
g(x) = 3x - 7
g(x) = 0
3x - 7 = 0
3x = 0 + 7
x = 7 / 3
Putting x = 7 / 3 in p(x)
p(7/3) = 6 ( 7 / 3 )³ + ( 7 / 3 )² - 26 ( 7 / 3 ) - 25
p(7/3) = 6 * 343 / 27 + 49 / 9 - 182 / 3 - 25
p(7/3) = 686 / 9 + 49 / 9 - 546 / 9 - 225 / 9
p(7/3) = 686 + 49 - 546 - 225 / 9
p(7/3) = 735 - 771 / 9
p(7/3) = -36/9
p(7/3) = -4
As p(7/3) ≠ 0 so g(x) is not a factor of p(x).
So 3x-7 is not a factor of 6x³ - x² - 26x -25
Similar questions