Question

Check whether - 4 and 4 are zeroes of the polynomial p(x) = x^2+16.​

Answer 1

Answer:

no

Step-by-step explanation:

(x+4)(x-4)

x2-4x+4x-16

x2-16

so -4 & 4 ready zeroes of x2-16 not of x2+16.

Answer 2

Answer:

Let us substitute x=−2 in the given polynomial f(x)=x4−16 as shown below:

f(−2)=(−2)4−16=16−16=0

Since f(−2)=0, therefore, −2 is the zero of the polynomial f(x)=x4−16.

Now substitute x=2 as shown follows:

f(2)=(2)4−16=16−16=0

Since f(2)=0, therefore, 2 is the zero of the polynomial f(x)=x4−16.

Hence, −2 and 2 are the zeroes of the polynomial f(x)=x4−16.

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