Check whether (41)" can end with digit 0 for any natural number n
Answers
.Answer:
Step-by-step explanation:
A digit ending with zero must need to have 2 and 5 as factors or the number itself should have ended with the digit zero.
The factors of 4 = 2×2
It has only 2 as a factor and 5 is missing.
Hence we cannot get zero at end of the value .
Where n = any natural number starting from 1
Answer:
If the number 4n, for any n, were to end with the digit zero, then it should be divisible by 5. That is, prime factorisation of 4n would contain the prime factor 5. This is not possible because 4n=(22)n=22n. So, the only prime in the factorisation of 4n is 2.
So, by uniqueness of the fundamental theorem of Arithmetic, there are no other primes in the factorisation of 4n.
Hence, there is no natural number 'n' for which 4n. ends with the digit zero.
Step-by-step explanation: