check whether 4n can end with the digit 0 for any natural number n
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This is not possible beacuse 4n =22n; so the only prime in the factorization of 4n is 2. So the uniqueness of the Fundamental Theorem of Arthmetic guarantees that there are no other primes in the factorization of 4n . So there is no natural number n for which 4n ends with the digit zero.
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Step-by-step explanation:
Here if it is 4 to the power n, then it is not possible because for any natural number to end with 0, you need both 2 and 5. Here for 4, the factors are 2 multiplied to 2.
The same case if it is 4 multiplied to 'n', then there is a chance because n can be anything. It can be 5 or 25. It depends on the question.
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