Math, asked by hemayadav268, 10 months ago

check whether 6^ can and with the digit 0 for any natural number n​

Answers

Answered by swethaiyer2006
0

Answer:

Step-by-step explanation:

If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5

Prime factorisation of 6n = (2 ×3)n

It can be observed that 5 is not in the prime factorisation of 6n.

Hence, for any value of n, 6n will not be divisible by 5.

Therefore, 6n cannot end with the digit 0 for any natural number n.

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