Check whether 6" can end with the digit 0 for any natural number n.
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It can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.
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No, 6^n cannot end with the digit 0 for any natural number n. This is because the prime factors of 6 are 2 and 3. [(2 × 3)^n]
Since 5 isn't a prime factor of it, 6" cannot end with the digit 0 for any natural number n.
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