check whether 6 can end with the digit 0 for any natural number N
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Given,
6^n. ( where n belongs to N)
6°=1
6^1=6
6^2=36
6^3=216
No, 6^n can never end with 0, because 6 power any value in unit place is positive...
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shams21:
prove that the following are originals 1 upon root 2
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