Question

Check whether 6^n can end with digit 0 for any natural number n

Explain with correct procedure
It's a humble request.........

Answer 1

If the number 6n ends with the digit zero,then it is divisible by 5.Therefore the prime factorization of 6n contains the prime 5.This is not possible because the only with the digit zero.

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Answer 2

Answer:

In the care of any number with digit zero, it is likely for the numeric value to get divided by 5. In any case of a numeric number ending with 0 and 5, it must be divisible by 5.

Given:

We have been given a natural number like n and a numeric value 0 for 6^n.

To find:

We have to check whether 6^n can end with digit zero for any natural number n.

Solution:

According to the question,

Let n = 5

If any number end with zero or five, it must be divisible by 5.

For this reason, it can be stated that the prime factor of the value 6^n does not contain 5 as the prime number. Therefore, it is proved that 6^n cannot end with zero for any natural number n

Final answer:

6^n cannot end with digit zero for any natural number n.

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