Question

check whether 6^n can end with the digit 0 for any natural no n.​

Answer 1

Let 6^n end with digit 0

It means 2 and 5 will factor of 6^n

Actual factor of 6^n = (2×3)^n

[ Fundamental theorem of Arithmetic guarantees than 6^n have no other factor]

6^n = (2×3)^n not contain 5

Hence 6^n cannot ends with digit zero.

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