Question

check whether 6² can end with digit 0 for any natural number n

Answer 1

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Step-by-step explanation:

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Answer 2

:

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If any digit has the last digit 10 that means it divisible by 10.

The factor of 10=2×5,

So value of 6^n should be divisible by 2 and 5.

Both 6^n is divisible by 2 but not divisible by 5.

So, it can not end with 0.