Question

check whether 6can end with the digit 0for any natural number n​

Answer 1

Answer:

Step-by-step explanation:

6^n =(2×3)^n

=2^n ×3^n

6 cannot end with digit 0for any natural number n because any no.ending with digit 0 for natural no.n should have prime factors in the form 2^n × 5^m.

But since the prime factors of 6 are not in the form of 2^n × 5^m therefore it can never end with digit 0 for any natural no. n

If the explanation is not sufficient u can see it in ncert class 10 book's example.

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