Question

Check whether 6n can end with digit 0 for any natural number N

Answer 1

Answer:

If 6n will end with digit 0 then it must be divisible by 5 and 0.

But,

6n=2×3n means including only 2 and 3 as prime factors.

Hence, 6n cannot be end with digit 0

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Answer 2

$6^n$ can't end with the digit 0 for any natural number N

Step-by-step explanation:

A number ends with the digit 0, it should be divisible by 10 and we factor by division prime factorization is 2 x 5 which means it is also divisible by 2 and 5.

Prime factorization of $6^n$ = $(2\times3)^n$

It can be observed that 5 is not a prime factor of $6^n$.

Hence, for any value of n ,$6^n$ will not be divisible by 5 because it is not a prime factor of 5.

$\therefore$$6^n$  can not end with the digit 0 for any natural number N such as 1,2,3,4,5 etc.