Question

check whether 6n can end with the digit 0 for any natural number n​

Answer 1

No.

For any number to end with 0, it should have factors 2 and 5.

Here, 6^n = (2×3)^n .

The factors of 6 are 2 and 3 .

So, we observe that there is no 5.

Hence, we conclude that any number which is of the form 6^n cannot end with 0.

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Answer 2

Answer:

any digit has the last digit 10 that means it divisible by 10.

The factor of 10=2×5,

So value of 6

n

should be divisible by 2 and 5.

Both 6

n

is divisible by 2 but not divisible by 5.

So, it can not end with 0.