check whether 6n can end with the digit 0 for any natural n .
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If the number 6^n were to end with the digit 0, then it would have 5 and 2 as its prime factors, but we know that 6 has 2 and 3 as prime factors. So, there is no natural number n for which 6^n ends with a digit 0.
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Answer: N is a natural no
6n is divisible by 5
But the prime factor of 6 are 2 and 3
6n=(2*3)n
In the prime factor of 6n there is no factor of 5
There fore 6n dont end with 0
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