Check whether 6n can end with the digit 0 or 5 for any natural number n.
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the units place for multiple of 6 always be 0,2,4,6,8. so digit 0 qualifies not 5.
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if any number and with the digit 0, it should be divisible by 5.
prime factorization of 6n =(2×3)n
5 is not in prime factorization of 6n.
hence ,for any value of n 6 and will not be divisible by 5.
therefore,6 and cannot end with the digit 0 for any natural number n.
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