Math, asked by jagadeeswareddy8095, 11 months ago

Check whether (75)^n can end with zero for any n belongs to natural number

Answers

Answered by anubhav2017garg
23

Answer:No


Step-by-step explanation:

Let (75) ^n be a natural number that end with digit 0

But (75) ^n=(2×5) ^n which does not have 2 as a factor when we do it's factor is a ton

And fundamental theory of arithmetic says prime factor is a ton is unique

There is no other prime factor is a ton for (75) ^n

•°•Our supposition is wrong

(75) ^n does not end with digit 0 for any natural number n

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