Check whether (75)^n can end with zero for any n belongs to natural number
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Answer:No
Step-by-step explanation:
Let (75) ^n be a natural number that end with digit 0
But (75) ^n=(2×5) ^n which does not have 2 as a factor when we do it's factor is a ton
And fundamental theory of arithmetic says prime factor is a ton is unique
There is no other prime factor is a ton for (75) ^n
•°•Our supposition is wrong
(75) ^n does not end with digit 0 for any natural number n
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