Question

Check whether 8^n can end with the digit 0 for any natural number n.

Answer 1

Answer of your question

Hope it will help you.

Answer 2

Solution:-

If the number "8^n", for any natural number "n", is to end with digit 0, then it would be divisible by 2 and 5. This is not possible because

${8}^{n} = {( {2}^{3} )}^{n} = {(2 \times 2 \times 2)}^{n} .$

So, the uniqueness of the Fundamental Theorem of Arithmetic guarantees that there is no other prime accept "2" in the factorisation of "8^n" .

So, there is no natural number "n" for which "8^n" ends with digit "0".