check whether 8n can end with the digit '0' for any natural number 'n'
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Hey!
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Hey!
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Let us think of some numbers which end the digit 0
10 = 5 × 2
100 = 2 × 2 × 5 × 5
Many more...
Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.
But,
8^n = (4 × 2) ^n
It doesn't have 5 as it's factor thus 8^n cannot end with zero for any natural number n.
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Hope it helps...!!!
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