check whether 9^n can end with the digit 0 for any natural number n
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Answered by
23
Hey frnd !!!!☺
9^n cannot end with the digit 0 for any natural number n ...
This is becoz if any digit ends with zero it shld contain 2 and 5 has its factors.
But 9^n has 3^n and 3^n has factors...
Therefore by the fundamental theorem of arithmetic 9 n cannot end with zero..
Hope this helps u ☺
9^n cannot end with the digit 0 for any natural number n ...
This is becoz if any digit ends with zero it shld contain 2 and 5 has its factors.
But 9^n has 3^n and 3^n has factors...
Therefore by the fundamental theorem of arithmetic 9 n cannot end with zero..
Hope this helps u ☺
Hemamalini15:
Mark as brainliest
Answered by
19
heya mate here's your answer >>>
prime factorisation of 9 = 3×3
to end with digit 0 we need 2 and 5 in its prime factorisation but 2&5 are not present in the prime factorization of 9
so, we conclude that 9^n cannot be end with 0 when n is any natural number
hope this helps you
prime factorisation of 9 = 3×3
to end with digit 0 we need 2 and 5 in its prime factorisation but 2&5 are not present in the prime factorization of 9
so, we conclude that 9^n cannot be end with 0 when n is any natural number
hope this helps you
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