check whether a^4-b^4 is completely divisible by a-b or not.
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If a and b are two odd positive integers then (a^4-b^4) is divisible by?
Well, (a^4-b^4) can be factorized as (a^2+b^2)(a+b)(a-b). So the (a^4-b^4) can be divided by either of (a^2+b^2), (a+b) or (a-b).
Example: Let a = 11 and b = 9. Then
(a^4-b^4) = (a^2+b^2)(a+b)(a-b) or (11^2+9^2)(11+9)(11–9) or (121+81)*20*2 or 202*20*2.
(a^4-b^4) = 11^4–9^4 = 8080.
8080/202 = 40
8080/20 = 404
8080/2 = 4040
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