Question

check whether (a+b),(a+1)+b,(a+1)+(b+1),(a+2)(b+1),(a+2)(b+2) is an arithmetic progression and find common difference d ​


plzz answer

Answer 1

Step-by-step explanation:

Common difference = d = t_(n+1) - t_n

d = (a+b+1) - (a+b) = (a +b+2) - (a+b+1) = (a+b+3) - (a+b+2) = (a+b+4) - (a+b+3)

d = 1 = 1 = 1 = 1

Hence it's common difference is same or equal.

this implies, these are in AP series

Note:- In your ques i think you have done mistake. It should be like,

check whether (a+b),(a+1)+b,(a+1)+(b+1),(a+2)+(b+1),(a+2)+(b+2) is an arithmetic progression and find common difference d