Question

check whether a number is Armstrong number or not​

Answer 1

n=int(input("Enter any number: "))

a=n

arm=0

while n>0:

m=n%10

arm=arm+m*m*m

n=n//10

if a==arm:

print(a,"is an Armstrong number.")

else:

print(a,"is not an Armstrong number.")

Hope this helps you

Have a great day