check whether an=2021 ap or not
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Given : aₙ = 2021
To Find : whether aₙ = 2021 is in AP or not
Solution:
aₙ = 2021
aₙ = a + (n - 1)d
a + (n - 1)d = 2021
aₙ = 2021 is independent of n
=> a₁ = 2021 , a₂ = 2021 and so on
d = a₂ - a₁
= 2021 - 2021
= 0
Hence this is an AP with
a = 2021 and d= 0
a = first term , d = common difference
All terms of the AP are 2021
2021 , 2021 , 2021 , 2021 , ... and so on
Hence aₙ = 2021 is in an AP
Learn More:
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In an A.P if sum of its first n terms is 3n square +5n and it's Kth term ...
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