Check whether f(x) = 4x^3 + 4x^2 – 1x – 1 is a multiple of 2x + 1
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Step-by-step explanation:
Given :-
f(x) = 4x^3 + 4x^2 – 1x – 1
To find :-
Check whether f(x) = 4x^3 + 4x^2 – 1x – 1 is a multiple of 2x + 1 ?
Solution :-
Given Polynomial is f(x) = 4x³ + 4x² - 1x -1
=> (4x³ + 4x²) - (1x + 1 )
=> 4x²(x+1) -1(x+1)
=> (x+1)(4x²-1)
=> (x+1)(2²x²-1²)
=> (x+1)[(2x)²-1²]
We know that
(a+b)(a-b)=a²-b²
Where , a= 2x and b = 1
=> (x+1)(2x+1)(2x-1)
=> (2x+1)[(x+1)(2x-1)]
So, We have
(2x+1) is the one of the factors of f(x)
f(x) = 4x³ + 4x² - 1x -1 = (2x+1)[(x+1)(2x-1)]
It is clear that
f(x) is a multiple of (2x+1)
Hance, Verified.
Answer:-
f(x) = 4x³+4x²-1x-1 is a multiple of 2x + 1.
Used Method:-
- Factorization method
Used formulae:-
- (a+b)(a-b)=a²-b²
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