Question

Check whether g(x) is a factor of p(x) by dividing polynomial p(x) by polynomial g(x) where p(x) =x^5-4x^3+ x^2 +3x +1 g(x) = x^³ -3x ±1

Answer 1

Answer:

g(x) is not factor of p(x)

Step-by-step explanation:

g(x) is factor of p(x) if their division leaves 0 As remainder.

We divide p(x) by g(x) using long divison method,

1). $p(x)=x^5-4x^3+x^2+3x+1$

$g(x)=x^3-3x+1$

Division is attached.

Remainder =  2

So, g(x) is not factor of p(x)

2). $p(x)=x^5-4x^3+x^2+3x+1$

$g(x)=x^3-3x-1$

Division is attached.

Remainder =  2x²

So, g(x) is not factor of p(x)

Therefore, g(x) is not factor of p(x)

Answer 2

Answer:

Bhai iska 3rd wlaa hai kya kya