Math, asked by adityagprime, 1 year ago

Check whether m²-1 is divisible by 6 if m is a) an integer b) a natural no c) odd integer d) even integer

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Answered by zaidazmi8442
0
for \: divible \: 6\: \: \: \: \: ( {m}^{2} - 1) \: should \\ \: be \: even \\ so \: \: {m}^{2} - 1 = 2k \: where \: k \: positive \\ integer \\ {m}^{2} = 2k + 1 \: is \: odd \\ square \: of \: any \: numer \: is \: odd \: \\ then \: number \: is \: also \: odd \\ {x}^{2} = odd \: integer \\ then \: x \: is \: odd \\ i \: realise \\ so \: m \: is \: odd \: integer
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