check whether minus 3 is a solution of the equation 3 X square + 5 x + 2 is equals to zero
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Answered by
1
3x2+2kx−3=0
Solutions are,
x=−2k±4k2+4∗3∗3√2∗3
x=−k±k2+9√3
Since it is given that x=−12,
−k±k2+9√3=−12
−k±k2+9−−−−−√=−32
k2+9=(k−32)2=k2−3k+94
3k=94−9
k=−94
Answered by
0
Step-by-step explanation:
3x2+2kx_3=0 solutions are
x=2k+4k2+》*3^2
since it is given that x=12
_k +k2+9------------^=_32
k2 +9 =(k_32)2=k2_3k+94
3k=94_9
k=_94
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