check whether (p+1) is a factor of (p^100-1) and (p^101+1) Please give the correct answers!
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Answer:
Step-by-step explanation:
If (p+1) is a solution,,
Value of p=-1
(-1)^100-1
====> 1 - 1
====> 0
So,
P-1 is a factor of this equation
Equation (2)
(-1)^101+1
====> -1 + 1
====> 0
Thus p-1 is a solution to both of the equations
====> Replacing value of p in equation...
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