Question

Check whether
P(t)=6t power 3+3t power 2+3t+18 is multiply of (2t+3)

Answer 1

Answer:

2t + 3 is a multiple

Step-by-step explanation:

we get remainder as zero hence 2t + 3 is a multiple of

$6 {t}^{3} + 3 {t}^{2} + 3t + 18$

Answer 2

Answer:

Yes, P(t) is a multiple of (2t+3)

Step-by-step explanation:

Here, 2t + 3 = 0

         2t = 0-3

         2t = -3

          t = -3/2

p(t) = 6t^3 + 3t^2 + 3t + 18

p(-3/2) = 6 * (-3/2)^3 + 3 * (-3/2)^2 + 3 * -3/2 + 18

           = -81/4 + 27/4 + -9/2 + 18

           =  -54/4 + -9/2 + 18

           = -72/4 +18

           = -18 + 18

           = 0

So, by the result of 0, it is proven that p(t) is a multiple of (2t+3)