Math, asked by sisa1737, 1 year ago

Check whether p(x) is a multiple of g(x) or not where p(x)=x^+2x+2 g(x)=x+1

Answers

Answered by khyathis
0
hey here is ur answer

since remainder is 1 and not 0

therefore g(x) Is not a factor.

I hope this helps you
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Answered by ParthThakre9965
0

by factor theorem,

x+1=0

x=-1

by remainder theorem,

p(1)=remainder

(-1)^2+2(-1)+2

=1-2+2

=1

but, 1 is not equal to 0

so g(x) is not a factor of p(x)

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