Check whether p(x) is a multiple of g(x) or not where p(x)=x^+2x+2 g(x)=x+1
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hey here is ur answer
since remainder is 1 and not 0
therefore g(x) Is not a factor.
I hope this helps you
since remainder is 1 and not 0
therefore g(x) Is not a factor.
I hope this helps you
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Answered by
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by factor theorem,
x+1=0
x=-1
by remainder theorem,
p(1)=remainder
(-1)^2+2(-1)+2
=1-2+2
=1
but, 1 is not equal to 0
so g(x) is not a factor of p(x)
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