Check whether p(X) is a multiple og6 g(X) where p(X)=x³-x+1, g(X)=2-3x
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=g (x)=0
=2-3x=0
=-2=-3x
=x=2/3
p (x) = x cube -x+1
p (2/3)=2/3cube-2/3+1
=8/27-2/2+1
=8-18+27/27
=35-18/27
x= 17/27
P (x) is not equal to zero
Therefore it p (x) is not a multiple of g (x)
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