check whether polynomial x-1 is a factor of x cube-8xsquare+19x-12
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go through the solution step by step
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Answered by
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p[x] = x³-8x²+19x-12
p[1]=[1]³-8[1]²+19[1]-12
=1-8+19-12
=0
thus [x-1] is a factor
p[1]=[1]³-8[1]²+19[1]-12
=1-8+19-12
=0
thus [x-1] is a factor
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