check whether pt is the factor of QC p = po 1
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Answer:
Yes
Step-by-step explanation:
If p + 1 = 0, p = -1
Q (p) = p¹⁰⁰ - 1
Substituting this value in Q (p), we get
(-1)¹⁰⁰ - 1 = 1 - 1 = 0
So, p + 1 is the factor of Q (p)
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