Question

check whether(t+1) is a factor of 4t³+3x²+3x-1​

Answer 1

Mistake in question:

Correct question:

Check whether ( t + 1 ) is a factor of $\large 4t^3+3t^2+3t-1$

Answer:

( t + 1 ) is not factor of p ( x ).

Step-by-step explanation:

Given :

$\large p(x)=4t^3+3t^2+3t-1 \ and \ g(x)=t+1$

Being factor remainder should be 0

Now putting t = -1 in p ( x ) and check remainder is zero or not.

$\large p(x)=4t^3+3t^2+3t-1\\\\\\\large p(-1)=4(-1)^3+3(-1)^2+3(-1)-1\\\\\\\large p(-1)=-4+3-3-1\\\\\\\large p(-1)=-4-1\\\\\\\large p(-1)=-5$

Since remainder is not zero.

( t + 1 ) is not a factor of p ( x ).

Thus we get answer.