Question

Check whether t^3 - 2t ^2 + 3t -18 is exactly divisible by ( t -3 ) or not ​

Answer 1

t-3 = 0 ( zero of the polynomial)

t= 3

put (t) = 3

3^3 - 2^(3)^2 + 3^3 -18

9- 18 + 9-18 = 0

hence, proved that t^3 - 2t^2 + 3t -18 is divisible by (t-3)

Answer 2

Yes

Quotient q(x)= t^2+t+6

Remainder r(x)= 0