Question

Check whether
$2 {x}^{2} - x + \frac{1}{8} = 0$
has real roots or not.
Please explain clearly​

Answer 1

2x²-x+1 = 0

8

multiply both side of equation by 8.

2x²×8-x×8+1 × 8= 0

8

16x²-8x+1=0

compare equation with ax²+bx+c=0

a=16, b=-8,c=1

b²-4ac= (-8)²-4×16×1

= 64-64

=0

b²-4ac=0

there fore, root's of equation is real and equal.